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commit

[ Edited ]
Wednesday

hi all,

1-) Why there is a difference between ">show system rollback compare 5 6" and  ">show system rollback compare 6 5"

 

 

2-) In order to find what change occured at the number 6, what exact command should be used?

>show system commit
0

1

2

3

4

5

6 2019-07-18 09:25:23 Eux by CUTO01 via cli



10 

7 REPLIES 7
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Re: commit

Wednesday

hi 

 

You may try this 

 

labroot@springwater> edit
Entering configuration mode

[edit]
labroot@springwater# rollback 6
load complete

[edit]
labroot@springwater# show | compare

here you will see the config 

 

Then do a rollback and exit ,which will not commit rollback 6 command 

[edit]
labroot@springwater# rollback
load complete

[edit]
labroot@springwater# exit
Exiting configuration mode

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Re: commit

Wednesday

Or you can use below command as well to dsplay the config change 

 

labroot@springwater> show system rollback 5 compare 6

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Re: commit

Wednesday

Answering your first question, 

 

Example 

 

This command shows the configuration commit change between 5 and 6 

 

show system rollback 5 compare 6   > This show what was commmit in 5 compared with 6 ( in below example filter was deativated in the commit )

 

show system rollback 6 compare 5 > This shows what was commit in 6 compared with 5 ( in below example filter was ativated in the commit )

 

labroot@springwater> show system rollback 5 compare 6
[edit interfaces ae2 unit 0 family inet filter]
! inactive: input { ... }
[edit interfaces ae2 unit 0 family inet6 filter]
! inactive: input { ... }

labroot@springwater> show system rollback 6 compare 5
[edit interfaces ae2 unit 0 family inet filter]
! active: input { ... }
[edit interfaces ae2 unit 0 family inet6 filter]
! active: input { ... }

 

Thank you

Prabin

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Solution
Accepted by topic author Arix
Thursday

Re: commit

Thursday

"In order to find what change occured at the number 6, what exact command should be used?" - you'll need to compare it with the previous configuration that was present (e.g. was committed during the previous commit). In your case, it will be commit #7, and the correct answer is "show system rollback compare 7 6".

 

This example should make it clear - let's see what was committed during the last commit (#0):

[edit]
user@mx# set interfaces lo0.0 description test1

[edit]
user@mx# commit and-quit
commit complete
Exiting configuration mode

user@mx> show system commit
0   2019-10-10 09:48:28 CEST by user via cli
1   2019-10-08 11:32:30 CEST by root via other

user@mx> show system rollback compare 1 0
[edit interfaces lo0 unit 0]
+    description test1;

Best regards,

Sergii

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Re: commit

Thursday

What about >show system rollback compare 0 1? Can you show result?

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Re: commit

Thursday

Here it is:

user@mx> show system rollback compare 0 1
[edit interfaces lo0 unit 0]
- description test1;

The delta shown should be applied (description removed) to the first argument - configuration commit #0 in order to get the second argument - configuration commit #1.

 

Best regards,

Sergii

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Re: commit

Thursday

Hello Arix,

 

Thanks for kudos, much appreciated.

Can you please also accept one of the posts as the solution, if now everythign is clear for you? It will mark this question as answered and help other community users find the solution faster should they have the same query.

 

Best regards,

Sergii

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